Cost function=400Q-50Q^2+5Q^3
What is the level of output at which the production of the uniform minimize the company's ATC
TC=400Q−500Q2+5Q3TC = 400Q-500Q^2+5Q^3TC=400Q−500Q2+5Q3
ATC=TCQ=400−500Q+5Q2ATC =\frac{TC}{Q}=400-500Q+5Q^2ATC=QTC=400−500Q+5Q2
find min ATC:\text{find min ATC:}find min ATC:
ATC′=(400−500Q+5Q2)′=−500+10QATC'=(400-500Q+5Q^2)'=-500+10QATC′=(400−500Q+5Q2)′=−500+10Q
ATC′=0;−500+10Q=0;Q=50ATC'=0;-500+10Q=0;Q=50ATC′=0;−500+10Q=0;Q=50
ATC′(49)=−500+490=−10<0ATC'(49)=-500+490=-10<0ATC′(49)=−500+490=−10<0
ATC′(51)=−500+510=10>0ATC'(51)=-500+510=10>0ATC′(51)=−500+510=10>0
hence Q=50minimum point of function ATC\text{hence } Q=50 \text{minimum point of function }ATChence Q=50minimum point of function ATC
Answer: 50\text{Answer: }50Answer: 50
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