Given the following demand function for beef (kg), P = 200 – 5Q i) By how much would the price have to fall for consumers to be willing to buy 1 more kg of beef per day? [5 marks] ii) If the price decreases by N$0.9, by how much will the demand changed?
Solution:
i). Derive the inverse demand function:
P = 200 – 5Q
5Q = 200 – P
Q = "40 - \\frac{P}{5}"
When the beef is 1 kg, the price will be as follows:
Q = "40 - \\frac{P}{5}"
1 = "40 - \\frac{P}{5}"
5 = 40 – P
P = 40 – 5
P = 35
Consumers will pay N$35 for a kg of beef
When an extra beef of kg is added, the price will be as follows:
Q = "40 - \\frac{P}{5}"
2 = "40 - \\frac{P}{5}"
10 = 40 – P
P = 40 – 10
P = N$30
Price change = 35 – 30 = N$5
The price will have to fall by N$5 for the consumers to be willing to buy 1 more kg of beef per day.
ii). First derive demand at previous price of N$35:
Q = "40 - \\frac{P}{5}"
Q = "40 - (\\frac{35}{5} )"
Q = 40 – 7
Q = 33
Then derive the demand at the current price of N$34.1:
That is: 35 – 0.9 = N$34.1
Q = "40 - \\frac{P}{5}"
Q = "40 - (\\frac{34.1}{5} )"
Q = 40 – 6.82
Q = 33.18
The demand will change by: 33.18 – 33 = 0.18kg
The demand will increase by 0.18kg
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