Question

Consider the following demand 

Q=6000−3P

Find the maximum total revenue that the producer can get.

Answer 1

$$TR=pQ$$

$$p=2000-\frac{1}{3}Q$$

$$TR=2000Q-\frac{1}{3}Q^2$$

$$MR=2000-\frac{2}{3}Q$$

$$Q=3000$$

$$p=1000$$

$$TR=3000000$$