Question

Find the Euclidean distance between (1,3,4) (4,2,-5)

Answer 1

$d(p,q)=√((q1−p1)^ 2 +(q2−p2) ^ 2 +(q3−p3)^ 2 +...(qn−pn)^ 2$

$q1 = 1$

$q2 = 3$

$q3 = 4$

$p1 = 4$

$p2 = 2$

$p3 = -5$

$=√((4−1)^ 2 +(2−3) ^ 2 +(−5−4) ^ 2 ))$

$= √(3^2+1^+(−9^2))$

$= √9 + 1 + 81$

$= √91$

$= 9.5394$