Question #180296

Find the Euclidean distance between (2,5) (4,2)


1
Expert's answer
2021-04-21T13:06:03-0400

d(p,q)=((q1p1)2+(q2p2)2+...(qnpn)2d(p,q) = √((q1-p1)^2 + (q2-p2)^2 + ...(qn-pn)^2

q1=2q1 = 2

q2=5q2 = 5

p1=4p1 = 4

p2=2p2 = 2

=(((42)2+(25)2=√(((4−2) ^ 2 +(2−5)^ 2

=22+(3)2=√2 ^ 2 +(−3)^ 2

=4+9=√4+9

=13= √13

=3.6056= 3.6056



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