Answer to Question #169253 in Microeconomics for shreemanta kalita

Question #169253

 A monopolist faces the demand curve Q = 120 - P/3. The cost function is C = Q 3 . Find the output that maximises this monopolist’s profits. What are the prices at profits and that output? Find the elasticity of demand at the profit maximising output.


1
Expert's answer
2021-03-08T09:22:20-0500

Let's first write the inverse demand function:


P=3603Q.P=360-3Q.

By the definition of the total revenue, we have:


TR=PQ=(3603Q)Q=360Q3Q2.TR=PQ=(360-3Q)Q=360Q-3Q^2.

Then, we can find the marginal revenue:


MR=dTRdQ=3606Q.MR=\dfrac{dTR}{dQ}=360-6Q.

Let's find the marginal cost:


MC=dTCdQ=ddQ(Q3)=3Q2.MC=\dfrac{dTC}{dQ}=\dfrac{d}{dQ}(Q^3)=3Q^2.

The monopolist maximises its profit when MC=MR:


3Q2=3606Q,3Q^2=360-6Q,Q2+2Q120=0.Q^2+2Q-120=0.

This quadratic equation has two roots: Q1=10Q_1=10 and Q2=12Q_2=-12. Since the quantity produced can't be negative the correct answer is Q=10Q=10.

Then, we can find the price that maximises the profit:


P=3603Q=360310=$330.P=360-3Q=360-3\cdot10=\$330.

We can find the price elasticity of demand as follows:


ϵ=PQdQdP,\epsilon=-\dfrac{P}{Q}\dfrac{dQ}{dP},Q=P3603,dQdP=13,Q=\dfrac{P-360}{3}, \dfrac{dQ}{dP}=-\dfrac{1}{3},ϵ=3PP360(13)=PP360.\epsilon=-\dfrac{3P}{P-360}\cdot-(\dfrac{1}{3})=\dfrac{P}{P-360}.

The price elasticity of demand when P = $330 equals:


ϵ=$330$330360=11.\epsilon=\dfrac{\$330}{\$330-360}=-11.

Therefore, demand is elastic.


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