Question #162688

Consider the following short run production function: Q=6L2-0.4L3 

1. a) Find the value of L that maximizes output

b) Find the value of L that maximizes marginal product

c) Find the value of L that maximizes average product


1
Expert's answer
2021-02-10T21:38:48-0500

(a) Let's first find the marginal product:


MP=ddL(Q)=ddL(6L20.4L3)=12L1.2L2.MP=\dfrac{d}{dL}(Q)=\dfrac{d}{dL}(6L^2-0.4L^3)=12L-1.2L^2.

Then. we can find the value of L that maximizes output:


MP=0,MP=0,12L1.2L2=0,12L-1.2L^2=0,L=10.L=10.

b) Let's take the derivative from MP with respect to L:


ddL(MP)=ddL(12L1.2L2)=122.4L.\dfrac{d}{dL}(MP)=\dfrac{d}{dL}(12L-1.2L^2)=12-2.4L.

Then, we can find the value of L that maximizes marginal product:


122.4L=0,12-2.4L=0,L=5.L=5.

c) Let's find the AP:


AP=QL=6L20.4L3L=6L0.4L2.AP=\dfrac{Q}{L}=\dfrac{6L^2-0.4L^3}{L}=6L-0.4L^2.

Let's take the derivative from AP with respect to L:


ddL(AP)=ddL(6L0.4L2)=60.8L.\dfrac{d}{dL}(AP)=\dfrac{d}{dL}(6L-0.4L^2)=6-0.8L.

Then, we can find the value of L that maximizes average product:


60.8L=0,6-0.8L=0,L=7.5L=7.5

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