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Question #158211
Consider U=q
2
+q
2
Derive the Mashallian dd function from q1 and q2.
Expert's answer
δ
u
δ
q
1
=
2
q
1
\frac {\delta u}{\delta q_1}=2q_1
δ
q
1
δ
u
=
2
q
1
δ
u
δ
q
2
=
2
q
2
\frac {\delta u}{\delta q_2}=2q_2
δ
q
2
δ
u
=
2
q
2
M
U
1
p
1
=
M
U
2
p
2
\frac {MU_1}{p_1}=\frac {MU_2}{p_2}
p
1
M
U
1
=
p
2
M
U
2
2
q
1
p
1
=
2
q
2
p
2
\frac {2q_1}{p_1}=\frac {2q_2}{p_2}
p
1
2
q
1
=
p
2
2
q
2
I
=
p
1
q
1
+
p
2
q
2
I=p_1q_1+p_2q_2
I
=
p
1
q
1
+
p
2
q
2
q
2
=
p
2
p
1
q
1
q_2=\frac {p_2}{p_1}q_1
q
2
=
p
1
p
2
q
1
q
1
∗
=
I
p
1
p
1
2
+
p
2
2
q_1^*=\frac {Ip_1}{p_1^2+p_2^2}
q
1
∗
=
p
1
2
+
p
2
2
I
p
1
q
2
∗
=
I
p
2
p
1
2
+
p
2
2
q_2^*=\frac {Ip_2}{p_1^2+p_2^2}
q
2
∗
=
p
1
2
+
p
2
2
I
p
2
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