"q = 100 \\\\\n\n100 = 400-2p-p^2 \\\\\n\n0 = 300-2p-p^2\n\n-p^2-2p+300 = 0 \\\\\n\np_{1,2}=\\frac{-(-2)\u00b1\\sqrt{(-2)^2-4(-1) \\times 300}}{2(-1)} \\\\\n\np_{1,2}= \\frac{-(-2)\u00b1 2 \\sqrt{301}}{2(-1)} \\\\\n\np_1 = -1 - \\sqrt{301} = -18.35 \\\\\n\np_2 = \\sqrt{301}-1= 16.35"
Answer: p = 16.35
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