q=100100=400−2p−p20=300−2p−p2−p2−2p+300=0p1,2=−(−2)±(−2)2−4(−1)×3002(−1)p1,2=−(−2)±23012(−1)p1=−1−301=−18.35p2=301−1=16.35q = 100 \\ 100 = 400-2p-p^2 \\ 0 = 300-2p-p^2 -p^2-2p+300 = 0 \\ p_{1,2}=\frac{-(-2)±\sqrt{(-2)^2-4(-1) \times 300}}{2(-1)} \\ p_{1,2}= \frac{-(-2)± 2 \sqrt{301}}{2(-1)} \\ p_1 = -1 - \sqrt{301} = -18.35 \\ p_2 = \sqrt{301}-1= 16.35q=100100=400−2p−p20=300−2p−p2−p2−2p+300=0p1,2=2(−1)−(−2)±(−2)2−4(−1)×300p1,2=2(−1)−(−2)±2301p1=−1−301=−18.35p2=301−1=16.35
Answer: p = 16.35
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