First of all we will say
Budget30=9C+3SorS=10−3C
Therefore
U=S•C+10(S+C)=S•C+10S+10C=C(10−3C)+10(10−3C)+10C
Simplify to
U=10C−3C²+100−30C+10C=100−10C−3C²
this means
C≥0andfrombudget:C[MAX]=30/9≈3.33;atS=0
S≥0andfrombudget:S[MAX]=30/3=10.00;atC=0
3.33≥C≥0
0≤S≤10
Now maximize U(C)→MAX
100-10C-3C²→MAX & 10/3≥C≥0
∂U(C)/∂C= -10-3C < 0
Maximum will be a lower boundary since its downward sloping for all allowed ranges.
Therefore utility-maximizing solution backet is:C=0 & S=10 &U[MAX]=100.
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