The average product of labour is:
APL=Q/L=L×e−0.01L.APL = Q/L = L×e^{-0.01L}.APL=Q/L=L×e−0.01L.
APL is maximized if APL'(L) = 0, so:
(L×e−0.01L)′=e−0.01L−0.01L×e−0.01L=e−0.01L×(1−0.01L)=0,(L×e^{-0.01L}) ' = e^{-0.01L} - 0.01L×e^{-0.01L} = e^{-0.01L}×(1 - 0.01L) = 0,(L×e−0.01L)′=e−0.01L−0.01L×e−0.01L=e−0.01L×(1−0.01L)=0,
L = 100 or
e−0.01L=0e^{-0.01L} = 0e−0.01L=0, which has no roots.
Need a fast expert's response?
and get a quick answer at the best price
for any assignment or question with DETAILED EXPLANATIONS!
Comments