Solution:
Derive functions:
"500=(a\\times 10) + b"
"150=(a\\times 16) + b"
"350=-6a"
"a = \\frac{350}{-6}"
"a = -58.3"
Substitute from the function to get b:
"500 = (-58.3\\times 10)+b"
"500 = -583+b"
"500+583=b"
"b=1083"
Therefore:
"Q =-58.3P+1083"
Substitute to derive P:
"-58.3P+1083=Q"
"-58.3P=Q-1083"
"P=\\frac{-Q}{-58.3}-\\frac{1083}{-58.3}"
"P=-0.02Q+18.6"
Find TR:
"TR = (P\\times Q)"
"TR=(-0.02Q\\times Q) +(18.6\\times Q)"
"TR=-0.02Q^{2} +18.6Q"
Find MR:
The MR is the derivative of the total revenue with respect to demand:
Therefore:
"MR =-0.04Q+18.6"
Substitute to derive the Price:
"5=-0.04Q+18.6"
"0.04Q=18.6-5"
"Q=\\frac{13.6}{0.04}"
"Q=340"
Substitute for Price:
"P=-0.02Q+18.6"
"P=(-0.02\\times 340)+18.6"
"P=-6.8+18.6"
"P=11.8"
The price that should be charged is = 11.8
Comments
Leave a comment