Solution:
Derive functions:
500=(a×10)+b
150=(a×16)+b
350=−6a
a=−6350
a=−58.3
Substitute from the function to get b:
500=(−58.3×10)+b
500=−583+b
500+583=b
b=1083
Therefore:
Q=−58.3P+1083
Substitute to derive P:
−58.3P+1083=Q
−58.3P=Q−1083
P=−58.3−Q−−58.31083
P=−0.02Q+18.6
Find TR:
TR=(P×Q)
TR=(−0.02Q×Q)+(18.6×Q)
TR=−0.02Q2+18.6Q
Find MR:
The MR is the derivative of the total revenue with respect to demand:
Therefore:
MR=−0.04Q+18.6
Substitute to derive the Price:
5=−0.04Q+18.6
0.04Q=18.6−5
Q=0.0413.6
Q=340
Substitute for Price:
P=−0.02Q+18.6
P=(−0.02×340)+18.6
P=−6.8+18.6
P=11.8
The price that should be charged is = 11.8
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