Question #143128
Imagine you've started a new pizza restaurant. It costs you about $5 to produce a pizza.

Last week you sold 500 pizzas for $10 each.

This week you raised your price and sold 150 pizzas for $16 each.

What price should you be charging?
1
Expert's answer
2020-11-17T12:24:41-0500

Solution:

Derive functions:

500=(a×10)+b500=(a\times 10) + b

150=(a×16)+b150=(a\times 16) + b

350=6a350=-6a

a=3506a = \frac{350}{-6}

a=58.3a = -58.3

Substitute from the function to get b:

500=(58.3×10)+b500 = (-58.3\times 10)+b

500=583+b500 = -583+b

500+583=b500+583=b

b=1083b=1083

Therefore:

Q=58.3P+1083Q =-58.3P+1083

Substitute to derive P:

58.3P+1083=Q-58.3P+1083=Q

58.3P=Q1083-58.3P=Q-1083

P=Q58.3108358.3P=\frac{-Q}{-58.3}-\frac{1083}{-58.3}


P=0.02Q+18.6P=-0.02Q+18.6


Find TR:

TR=(P×Q)TR = (P\times Q)

TR=(0.02Q×Q)+(18.6×Q)TR=(-0.02Q\times Q) +(18.6\times Q)

TR=0.02Q2+18.6QTR=-0.02Q^{2} +18.6Q


Find MR:

The MR is the derivative of the total revenue with respect to demand:

Therefore:

MR=0.04Q+18.6MR =-0.04Q+18.6


Substitute to derive the Price:

5=0.04Q+18.65=-0.04Q+18.6

0.04Q=18.650.04Q=18.6-5

Q=13.60.04Q=\frac{13.6}{0.04}


Q=340Q=340


Substitute for Price:

P=0.02Q+18.6P=-0.02Q+18.6

P=(0.02×340)+18.6P=(-0.02\times 340)+18.6

P=6.8+18.6P=-6.8+18.6

P=11.8P=11.8


The price that should be charged is = 11.8



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