As per the given question,
y=x1x2
Now,
L=w1x1+w2x2+λ(y−x1x2)
0=dλdy=y−x1x2
0=dλdy=w1−λx2
0=dλdy=w2−λx2
So, λ=x2w1=x1w2
We know that 4=w1x1+w2x2
4=w1x1+w2w1×x1w2
x1=2w14=w12
x2=w22
Hence, y=x1x2
y=w1×w22×2
y=4
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