profit maximize condition will be achieved
at MR = MC
"10-2a = 0"
"2a = 10"
"a = 5"
total revenue = price "\\times" quantity
TR = PQ
TR = "\\int" MR "d\\theta"
TR "= \\int""(10-2a)d\\theta"
TR = "10a-a^2"
"p= \\frac{TR}{a}"
"= \\frac{(10-a^2)}{a}"
"= 10-a"
"p= 10-5"
"=5"
market price of water per liter = $5
Comments
This was very helpful thank you.
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