profit maximize condition will be achieved
at MR = MC
10−2a=010-2a = 010−2a=0
2a=102a = 102a=10
a=5a = 5a=5
total revenue = price ×\times× quantity
TR = PQ
TR = ∫\int∫ MR dθd\thetadθ
TR =∫= \int=∫(10−2a)dθ(10-2a)d\theta(10−2a)dθ
TR = 10a−a210a-a^210a−a2
p=TRap= \frac{TR}{a}p=aTR
=(10−a2)a= \frac{(10-a^2)}{a}=a(10−a2)
=10−a= 10-a=10−a
p=10−5p= 10-5p=10−5
=5=5=5
market price of water per liter = $5
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This was very helpful thank you.
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This was very helpful thank you.