Solution For the even player, the expected payoff on player 1 is
+1.(x−1).(1−x) and for player 2 −1.x+1.(1−x)and those must be equal, so, x=0.5For the odd player the expected payoff when player 1 plays, +1.y+1.(1−y) and those must be equal so ,y=0.5
Note: x is player 1's probability of odd and y is player 1's probability of Even.
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