"Solution"
For the even player, the expected payoff on player 1 is
"+1.(x-1).(1-x)\\ and\\ for\\ player\\ 2\\ -1.x+1.(1-x) and\\ those\\ must\\ be\\ equal,\\ so,\\ x=0.5\\\\\nFor\\ the\\ odd\\ player\\ the\\ expected\\ payoff\\ when\\ player\\ 1\\ plays,\\ +1.y+1.(1-y)\\ and\\ those\\ must\\ be\\ equal\\ so\\ ,y=0.5"
Note: x is player 1's probability of odd and y is player 1's probability of Even.
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