Answer to Question #127502 in Microeconomics for fariza

Question #127502

1.1) You lend a friend RM20,000 for a year. At the end of the year your friend agrees to pay you RM21,100. The interest rate on this loan is _______

Working Calculation:


1.2) You lend a friend RM20,000 for a year at an annual interest rate of 5%. At the end of the year your friend must pay you ________ in interest.

Working Calculation:


1.3) You agree to lend ________ to a friend for a year at an annual interest rate of 10%. At the end of the year your friend pays you RM600 in interest.

Working Calculation:








1
Expert's answer
2020-07-29T10:58:23-0400

1.1) The interest rate on this loan is 5.5%

Working calculation:

A=P(1+r)tA=P(1+r)^{t}

RM21,100=RM20,000(1+r)1RM21,100=RM20,000(1+r)^{1}


RM21,100RM20,000=RM20,000RM20,000(1+r)\frac{RM21,100}{RM20,000}=\frac{RM20,000}{RM20,000}(1+r)


1.055=1+r1.055=1+r

r=1.0551r=1.055-1

r=0.055×100r=0.055\times100

r=5.5%r=5.5\%


1.2) The interest amount is RM 1,000

Working calculation:

A=P(1+r)1PA=P(1+r)^{1}-P

RM20,000(1+0.05)RM20,000RM20,000(1+0.05)-RM20,000

(RM20,000×1.05)RM20,000(RM20,000\times1.05)-RM20,000

RM21,000RM20,000RM21,000-RM20,000


Interest=RM1,000Interest=RM1,000


1.3) The amount lend will be RM 6,000

Working calculation:

Interest=APInterest=A-P

If10%=RM600=InterestIf 10\%=RM600=Interest

P=100%=?P=100\%=?

ThereforeP=100%10%×RM600Therefore P=\frac{100\%}{10\%}\times RM600


P=RM6,000P=RM6,000


Test to confirm the answer:

A=P(1+r)1PA=P(1+r)^{1}-P

RM6,000(1+0.1)1RM6,000RM6,000(1+0.1)^{1}-RM6,000

(RM6,000×1.1)RM6,000(RM6,000\times1.1)-RM6,000

RM6,600RM6,000RM6,600-RM6,000


Interest  amount=RM600Interest\; amount=RM600



Need a fast expert's response?

Submit order

and get a quick answer at the best price

for any assignment or question with DETAILED EXPLANATIONS!

Comments

No comments. Be the first!

Leave a comment