Question #122220
Q1) Haroon’s budget line relating good X and good Y has intercept of 100 unit of good X and 40 units of good Y. if the price of good X is 24, what is Haroon’s income? What is the price of good Y? What is then slope of budget line?
1
Expert's answer
2020-06-15T11:12:18-0400

The budget line will take the form of:



M=xPx+yPyM = xP_x + yP_y

Solving for yy in the budget line:



y=MPyPxPyxy = \dfrac{M}{P_y} - \dfrac{P_x}{P_y} x

Where:


  • M is the income
  • PyP_y is the price of good Y and,
  • PxP_x is the price of good X.

Here, the slope of the budget line is PxPy-\dfrac{P_x}{P_y}

At the y-intercept, the value of good X consumed is zero. Therefore:



M=yPyM = yP_y

Solving for ''y'', we get:



y=MPyy = \dfrac{M}{P_y}

At the y-intercept, y = 40. Therefore:



40=MPy40 = \dfrac{M}{P_y}

Solving for PyP_y :



Py=M40P_y = \dfrac{M}{40}

At the x-intercept, the amount of Y consumed is zero. Therefore:



M=xPxM = xP_x

Solving for ''x'':



x=MPxx = \dfrac{M}{P_x }

The x-intercept is 100. Therefore:




100=MPx100 = \dfrac{M}{P_x }

Solving for PxP_x :



Px=M100P_x = \dfrac{M}{100}

Therefore, the slope is:



PxPy=M100M40-\dfrac{P_x}{P_y} = -\dfrac{\dfrac{M}{100}}{\dfrac{M}{40}}

PxPy=M100×40M-\dfrac{P_x}{P_y} = -\dfrac{M}{100}\times \dfrac{40}{M}

PxPy=0.4-\dfrac{P_x}{P_y} = \color{red}{-0.4}


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