Point elasticity is given by ΔQΔP×PQ\frac{\Delta{Q}}{\Delta{P}}\times{\frac{P}{Q}}ΔPΔQ×QP
−4Q=P−24-4Q=P-24−4Q=P−24
Q=6−P4Q=6-\frac{P}{4}Q=6−4P
ΔQΔP=−14\frac{\Delta{Q}}{\Delta{P}}=-\frac{1}{4}ΔPΔQ=−41
P=12P=12P=12
Q(12)=6−124=3Q(12)=6-\frac{12}{4}=3Q(12)=6−412=3
E=−14×123=−1E=-\frac{1}{4}\times{\frac{12}{3}}=-1E=−41×312=−1
Thus, The correct answer is (c).
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