To transform to a matrix, the following guideline has to be adhered.
Y=C+I+G→Y−C=I+G
C=a+bY→ C−bY=a
T=tY→ T−tY
Y=C+I+G→Y=12+0.8Y+100+0.1Y+300
Y−0.9Y=412→Y=4120∴I=112+0.9(4120) =512
We then replace the values from the given equations where relevant, and placing a coefficient of zero to the missing constants in the guide equation.
1×Y−1×C+0×T=I+G
−0.8×Y+1×C+0×T=12
−t×Y+0×C+1×T=0
The matrix obtained from the variable coefficients become;
A= ⎣⎡1−0.8−t−11−0001⎦⎤ X= ⎣⎡YCT⎦⎤ Z= ⎣⎡I+G120⎦⎤ but I and G values are known.
I+G=512+300=812
so Z=⎣⎡812120⎦⎤
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