Answer to Question #292876 in Macroeconomics for Sheya

Question #292876

2. If 12% of a population of parts is defective, what is the probability of randomly selecting 60 parts and finding that 8 or more are defective?

Expert's answer

"P=C_{60}^8\\cdot 0.12^8\\cdot 0.88^{52}=0.14=14\\%."

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