TR=36x+3x2+56y−4y2TR=36x+3x²+56y-4y²TR=36x+3x2+56y−4y2
Budget constant 5y+10y=805y+10y=805y+10y=80
x+2y=16x=16−2yx+2y=16\\x=16-2yx+2y=16x=16−2y
TR=36(16−2y)+3(16−2y)2+56y−4y2TR=36(16-2y)+3(16-2y)²+56y-4y²TR=36(16−2y)+3(16−2y)2+56y−4y2
∆TR∆Y=−72y+6(16−2y)+56+8y\frac{∆TR}{∆Y}=-72y+6(16-2y)+56+8y∆Y∆TR=−72y+6(16−2y)+56+8y
∆TR∆Y=−104y+248=0\frac{∆TR}{∆Y}=-104y+248=0∆Y∆TR=−104y+248=0
y=248104y=\frac{248}{104}y=104248
x=16−496104=1168104x=16-\frac{496}{104}=\frac{1168}{104}x=16−104496=1041168
y=2.385x=11.231y=2.385\\x=11.231y=2.385x=11.231
Need a fast expert's response?
and get a quick answer at the best price
for any assignment or question with DETAILED EXPLANATIONS!
Comments