a.
"\\pi=TR-TC\\\\=(70q-q^2)-(q^2+30q+!00)\\\\=70q-q^2-q^2-30q-100\\\\=40q-2q^2-100"
necessary condition will be as dollows
"\\frac{\\delta \\pi}{\\delta q}=0\\\\40-4q=0\\\\4q=40\\\\q=10"
therefore the profit will be
"\\pi=TR-TC\\\\=40q-2q^2-100\\\\=40(10)-2(10)^2-100\\\\400-200-100\\\\=\\$100"
10 units will be produced to get a profit of $100
b.
the second order is "\\frac{\\delta ^2\\pi}{\\delta q^2}=0"
"\\frac{\\delta ^2\\pi}{\\delta q^2}=0\\\\\n\n\\frac{\\delta ^2(40-4q)}{\\delta q^2}\\leq0\\\\-4\\leq0"
c.
"MR=\\frac{d(TR)}{dq}\\\\=70-2q\\\\MC=\\frac{d(TC)}{dq}\\\\=2q+30\\\\MR=MC\\\\70-2q+30\\\\4q=40\\\\q=10"
the solution obeys the rule of mrginal revenue equa;s to marginal cost
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