a. We know . Substituting in the above equations, we get:
= Y – (3600 – 2000r + 0.1Y) – 1200
= – 4800 + 2000r + 0.9Y
This equation relates to the real interest rate (r) and output (Y).
b.
Y = (3600 – 2000r + 0.1Y) – (1200 – 4000r) – 1200
Y = 6000 – 6000r + 0.1Y
So, 0.9Y = 6000 – 6000r
At full employment, Y = 6000.
Substituting this into the above, we get 0.9x6000 = 6000 – 6000r
Finally, solving for r, we get r = 0.10 (or 10%).
– 4800 + 2000r + 0.9Y = 1200 – 4000r
0.9Y = 6000 – 6000r
When Y = 6000, r = 0.10 (or 10%).
So, we can use either Eq. (4.7) or (4.8) to get to the same result.
c. When G = 1440, desired saving becomes:
This becomes 0.9Y = 5040 – 2000r S^d is now 240 less for any given r and Y; this shows up as a shift in the from
What about r? Set , we get:
–5040 + 2000r + 0.9Y = 1200 – 4000r
6000r + 0.9Y = 6240
At Y = 6000, this is 6000r = 6240 – (0.9 x 6000) = 840, and so r = 0.14 (or 14%)
Thus, the market-clearing real interest rate increases from 10% to 14%.
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