Given:
Number of cars offered=100
Number of good cars=50
Probability of good car"=\\frac{50}{100}\\times 100=50 \\space or \\space 0.50"
Worth of good car=$10,000
Number of bad cars=50
Probability of lemon"=\\frac{50}{100}\\times 100=50 \\space or\\space 0.50"
Worth of bad car=$2000
a)
The maximum willingness of the buyer to pay for a car if he or she could not observe the quality of the car:
Given that the probability for each car is 0.50.
Computation of maximum willingness of buyer:
"=(Probability \\space for\\space good \\space car\\times Worth\\space of\\space good\\space car)+(Probability\\space for\\space bad\\space car\\times Worth\\space of\\space bad \\space car)\\\\=\\$ (0.50\\times 10,000)+(0.5\\times 2000)\\\\=\\$ (5000+1000)\\\\=\\$ 6000"
Hence, the maximum willingness of the buyer to pay is $6000.
b)
The market equilibrium if sellers value good cars at:
When the quality s not observable and the sellers tend to value the car at $8000 being more than the maximum willingness of the buyer to pay, then only lemons would be sold at "\\$(8000\u22126000)=\\$2000"
When the quality s not observable and the sellers tend to value the car at $6000 being more than the maximum willingness of the buyer to pay, then both good cars and lemons would be sold at $6000.
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