A.
1.
c=102+0.7y
i=150-100R
Ms=300
Mt=0.4y
Mz=15-200r
IS curve is given by;
Y= AD=C+I
y=102+0.7y + 150-100R
Making Y the subject
y=840-333.33r (IS Curve)
Money market
LM is given by;
Md=Ms
Md= Mt+ Mz
Md= 0.4y+125-200r
Md=Ms
0.4y+125-200r=300
Solving for Y
y=437.5+500r (LM Curve)
At equilibrium IS=LM
840-333.33r= 437.5+500r
Solving for r
r*= 0.48 (equilibrium interest rate)
substituting in y=840-333.33r
y*= 680(equilibrium income)
2.
c=102+0.7y
but y=680
c=102+0.7x680
c=578
i=150-100r
but r=0.48
i=150-100x0.48
i=102
Mt=0.4y
but y=680
Mt= 0.4x680
Mt=272
Mz=125-200r
M=125-200x0.48
Mz=29
B.
1.
In the open market involving the foreign market
IS= y= c+i+g+t+(x-m)
y=102+0.7y+150+100+(100-0.10y-50)
Solving for y
y=1255-250r (IS Curve)
In the money market
LM is the same as the one we calculated above
LM=437.5 +500r
At equilibrium
IS=LM
1255-250r=437.5 +500r
SOLVING FOR r
r= 1.09 - equiliobrium rate of interest
Substituting r = 1.09 in y=1255-250r
y= 982.5equilibrium income
2.
c=102+0.7y
but y= 982.5
c= 102+0.7x982.5
c=789.75
i=150-100r
but r=1.09
i=150-100x1.09
i=41
Mt=0.4y
but y= 982.5
Mt= 0.4 x 982.5
Mt=393
Mz=125-200r
but r=1.09
Mz=125-200x1.09
Mz=-93
3.
The BOP becomes perfectly horizontal
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