"( M\/P)=d1y-d2i\\\\\n(1-c_1-b_1)Y = c_0-c_1T+b_o-b_2 i +G\\\\\nMultiplier = \\frac{1}{1-c_1-b_1}"
Substituting for interest
"Y= \\frac{1}{(1-c_1-b_1+b_2d_1)\/d_2}[c_0-c_1T+b_0+ (\\frac{b_2}{d_2})(\\frac{M}{P})+G]"
Multiplier becomes
"\\frac{1}{(1-c_1-b_1+b_2d_1)\/d_2}"
Comments
Leave a comment