1) Assume the logarithmic transformation f a utility function, for the consumption of two commodities is given by
ln U = ln4 + 0.5ln X + 0.25lnY
(a) if the price of X is GHS2.50 and that of Y is GHS4.00, calculate the optimal combination for an income of GHS50.00.
b) Determine and interpret the value of the Lagrange multiplier.
logU=log4+0.5logX+0.25logYlog U =log 4+0.5 log X+0.25 log YlogU=log4+0.5logX+0.25logY
50=2.50X+4Y50=2.50X+4Y50=2.50X+4Y
L=log4+0.5logX+0.25logY+λ[50−2.50X−4Y]L=log 4+ 0.5log X +0.25 log Y+ \lambda [50-2.50X-4Y]L=log4+0.5logX+0.25logY+λ[50−2.50X−4Y]
δLδX=0.5X−λ(2.50)=0\frac {\delta L}{\delta X}=\frac {0.5}{X}-\lambda (2.50)=0δXδL=X0.5−λ(2.50)=0
δLδY=0.25Y−λ(4)=0\frac {\delta L}{\delta Y}=\frac {0.25}{Y}-\lambda(4)=0δYδL=Y0.25−λ(4)=0
0.52.50X=0.254Y\frac {0.5}{2.50X}=\frac {0.25}{4Y}2.50X0.5=4Y0.25
0.2X=0.0625Y\frac {0.2}{X}=\frac {0.0625}{Y}X0.2=Y0.0625
XY=0.20.0625\frac {X}{Y}= \frac {0.2}{0.0625}YX=0.06250.2
X=3.2YX= 3.2YX=3.2Y
50=2.50(3.2Y)+4Y50=2.50(3.2Y)+4Y50=2.50(3.2Y)+4Y
50=12Y50=12Y50=12Y
Y=4.16Y=4.16Y=4.16
X=13.33X=13.33X=13.33
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