Question #197049
Calculate the equilibrium price and quantity for the following functions

Qd1= -7p1 + 2p2 +19

Qd1= 4p1-5

Qd2= 4p1-4p2 +10

Qs2= 8p2-4



Solve by using inverse method and Cramer's rule
1
Expert's answer
2021-05-24T13:24:14-0400

Qd1=Qd14P15=7P1+2P2+194P1+7P1519=2P211P12242=2P211P1212=P2Qd_1=Qd_1\\4P_1-5=-7P_1+2P_2+19\\4P_1+7P_1-5-19=2P_2\\\frac{11P_1}{2}-\frac{24}{2}=2P_2\\\frac{11P_1}{2}-12=P_2


Qd=Qs4P14P2+10=8P2410+4=8P24P1+4P214=12P24P112P212=1412+4P112P2=142+412P1Qd=Qs\\4P_1-4P_2+10=8P_2-4\\10+4=8P_2-4P_1+4P_2\\14=12P_2-4P_1\\\frac{12P_2}{12}=\frac{14}{12}+\frac{4P_1}{12}\\P_2=\frac{14}{2}+\frac{4}{12}P_1


1412+412P1=112P112\frac{14}{12}+\frac{4}{12}P_1=\frac{11}{2}P_1-12


1412+12=112P11412P1\frac{14}{12}+12=\frac{11}{2}P_1-\frac{14}{12}P_1


13.1675.167=P1P1=2.548\frac{13.167}{5.167}=P_1\\P_1=2.548

Q1=4P15=4(2.548)5=5.192Q_1=4P_1-5\\=4(2.548)-5\\=5.192\\


P2=12P112P_2=\frac{1}{2}P_1-12

112×2.54812=2.014\frac{11}{2}\times2.548-12\\=2.014


Q2=8P24=8×2.0144=12.112Q_2=8P_2-4\\=8\times2.014-4\\=12.112


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