Question1. Given bellow are the cost and revenue functions of a perfect competitive firm:
TC= 20+10Q TR= 40Q-5Q2
Calculate:
a). Profit maximizing level of output
b) Total profit
Question 2. Determine shutdown price and output for the following total cost and total revenue functions:
TR=12Q TC=1/3Q3-9/2Q2+20Q+50
a). Find MR
b). MC Function
c). The quantity produced at shutdown point
d). The minimum price a firm will sell
Solution:
Question 1:
a). Profit maximizing level of output:
At profit-maximizing level of output: MR = MC
Derive MR:
MR = Derivative of TR with respect to the quantity
MR = "\\frac{\\partial TR_{} }{\\partial q_{} }" = 40 – 10Q
Derive MC:
MC = Derivative of TC with respect to the quantity
MC = "\\frac{\\partial TC_{} }{\\partial q_{} }" = 10
MR = MC
40 – 10Q = 10
40 – 10 = 10Q
30 = 10Q
Q = 3
Profit maximizing level of output = 3
b). Total profit
Total profit = TR – TC
TP = (20 + 10Q) – (40Q – 5Q2)
TP = (20 + 10(3)) – (40(3) – 5(32))
TP = (120 – 45) – (20 + 30)
TP = 75 – 50
TP = 25
Total profit = 25
Question 2:
a). Find MR:
MR = Derivative of TR to quantity
MR = "\\frac{\\partial TR_{} }{\\partial q_{} }" = 12
MR = 12
b). MC function:
MC = Derivative of TC to quantity
MC ="\\frac{\\partial TC_{} }{\\partial q_{} }" = Q2 – 9Q + 20
MC function = Q2 – 9Q + 20
c). Quantity produced at shut point:
The shutdown price is equal to the minimum AVC, a point where MC = AVC
Derive AVC:
AVC = "\\frac{VC }{Q }" = "\\frac{\\frac{1 }{3 }Q^{3} - \\frac{9 }{2 }Q^{2} + 20Q}{Q }"
AVC = "\\frac{1}{3}Q^{2} - \\frac{9}{2}Q + 20"
MC = Q2 – 9Q + 20
MC = AVC
Q2 – 9Q + 20 = "\\frac{1}{3}Q^{2} - \\frac{9}{2}Q + 20"
Q2 – 9Q = "\\frac{1}{3}Q^{2} - \\frac{9}{2}Q"
Q2 – "\\frac{1}{3}Q^{2}" – 9Q + "\\frac{9}{2}Q" = 0
"\\frac{2}{3}Q^{2}" – 13.5Q = 0
2Q2 – 40.5Q = 0
2Q (Q – 20.25) = 0
Q = 20.25
The quantity produced at shutdown point = 20.25
d). The minimum price the firm will sell:
P = MC
P = Q2 – 9Q + 20
P = 20.252 – 9(20.25) + 20
P = 410.06 – 182.25 + 20
P = 410.06 + 20 – 182.25
P = 247.81
The firm will sell at a minimum price of 247.81
Comments
Leave a comment