solution
given:C=100+0.8YI=120−5rMs=120Md=0.2Y−5r
[A] IS curve:Y=C+IY=100+0.8Y+120−5rY−O.8Y=220−5r0.2Y=220−5rY=1100−25r
[B] LM equation:Md=Ms0.2Y−5r=1200.2Y=120+5rY=600+25r
[C] Equilibrium income and interest rate:
interest rate at equilibrium IS=LM
1100−25r=600+25r1100−600=25r+25r500=50rr=10
income at equilibrium:
substitute:
Y=600+25rY=600+(25×10)Y=600+250Y=850
Y=1100−25rY=1100−(25×10)Y=1100−250Y=850
Therefore the equilibrium income is $850
[D] Equilibrium income if equilibrium interest rate increased by 25%
0.1=8500.25=?0.10.25×850=$2125
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