a) Answer
Q=1,400 Caps
Solution
When P = $6, Q=2,000−100(6)
=2,000−600
=1,400 caps
b) Answer
P=$2 per Cap
Solution
When Q=1,800 Caps
=>1,800=2,000−100P
=>100P=2,000−1,800
=>100P=200
P=100200
P=$2
c) Answer
Q=2,000 Caps
Solution
We need Q when P = $0
Thus, Q=2,000−100($0)
=2,000−0
=2,000 Caps
d) Answer
P=$20 per Cap
Solution
We need P when Q = 0 caps,
Thus, 0=2,000−100P
=>100P=2,000
=>P=1002,000
∴ P=$20 per cap
e) Answer
η=−0.429
Solution
η=dPdQ×Q0P0
When P=$6, Q=1,400 Caps
dPdQ=dPd(2,000−100P)
=−100
=>η=1−100×1,4006
=1−1×146
=−0.4285714285
=−0.429
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