Question #137706

ABC Sports, a store that sells various types of sports clothing and other sports items, is planning to introduce a new design of Arizona Diamondbacks’ baseball caps. A consultant has estimated the demand curve to be

Q = 2,000 - 100P

where Q is cap sales and P is price.

a. How many caps could ABC sell at $6 each?

b. How much would the price have to be to sell 1,800 caps?

c. Suppose ABC were to use the caps as a promotion. How many caps could ABC give away free?

d. At what price would no caps be sold?

e. Calculate the point price elasticity of demand at a price of $6.


Expert's answer

a) Answer\bold {Answer}

Q=1,400 CapsQ = 1,400 \space Caps


Solution\bold {Solution}

When P = $6, Q=2,000−100(6)Q = 2,000 - 100(6)

=2,000−600= 2,000 - 600

=1,400 caps= 1,400 \space caps



b) Answer\bold {Answer}

P=$2 per CapP = \$2 \space per \space Cap


Solution\bold {Solution}

When Q=1,800 CapsQ = 1,800 \space Caps

=>1,800=2,000−100P=> 1,800 = 2,000 - 100P

=>100P=2,000−1,800=> 100P = 2,000 - 1,800

=>100P=200=> 100P = 200

P=200100P = \dfrac {200}{100}

P=$2P = \$2


c) Answer\bold {Answer}

Q=2,000 CapsQ = 2,000 \space Caps


Solution\bold {Solution}

We need Q when P = $0

Thus, Q=2,000−100($0)Q = 2,000 - 100(\$0)

=2,000−0= 2,000 - 0

=2,000 Caps= 2,000 \space Caps



d) Answer\bold {Answer}

P=$20 per CapP = \$20 \space per \space Cap


Solution\bold {Solution}

We need P when Q = 0 caps,

Thus, 0=2,000−100PThus, \space 0 = 2,000 - 100P

=>100P=2,000=> 100P = 2,000

=>P=2,000100=> P = \dfrac {2,000}{100}


∴ P=$20\therefore \space P = \$20 per cap



e) Answer\bold {Answer}


η=−0.429\eta = -0.429


Solution\bold {Solution}

η=dQdP×P0Q0\eta = \dfrac {dQ}{dP} × \dfrac {P_{0}}{Q_{0}}


When P=$6, Q=1,400 CapsP = \$6, \space Q = 1,400 \space Caps


dQdP=ddP(2,000−100P)\dfrac {dQ}{dP} = \dfrac {d}{dP} (2,000-100P)


=−100= -100


=>η=−1001×61,400=> \eta = \dfrac {-100}{1} × \dfrac {6}{1,400}


=−11×614= \dfrac {-1}{1}×\dfrac {6}{14}


=−0.4285714285= -0.4285714285


=−0.429= -0.429


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