Question #137215

A monopolist operates under two plants, A and B. The marginal costs of these plants are given by 360 — 14x — 2x2and 310 — 15x — x2 with x representing units of output produced by each plant. If the price of the product is given by 396 — 4x2 , calculate the overall marginal cost and determine profit maximizing output in each plant.


Expert's answer

Plant 1: Mc1 =360−14x−2x2=360-14x-2x^2

Plant 2: Mc2 =310−15x−x2=310 - 15x -x^2


C1 = ∫\intopMc1 dx = 360x−7x−2x3/3360x-7x-2x^3/3


C2 = ∫\intMc2 dx = 310x−15x2/2−x3/3310x-15x^2/2-x^3/3


Total lost of the monopolist == C1 +C2

360x−7x2−2x3/3+310x−15x2/2−x3/3360x-7x^2-2x^3/3+310x-15x^2/2-x^3/3


670x−7x2−15x2/2−2x3/3−x3/3670x-7x^2-15x^2/2-2x^3/3-x^3/3


670x−(14x2−15x2)/2−x3670x-(14x^2-15x^2)/2-x^3


670x−(29x2)/2−x3670x-(29x^2)/2-x^3


Overall MC =670−29x−3x2= 670-29x-3x^2

For monopolist profit will be max.

MR=MCMR=MC

TR=P×QTR=P×Q

TR=(396−4x2)x=396x−4x3TR=(396-4x^2)x=396x-4x^3

MR=dTR/dx=396−12x2MR=dTR/dx=396-12x^2


in Plant 1 profit will be max

MR=MCMR=MC1

396−12x2=360−14x−2x2396-12x^2=360-14x-2x^2

36=−14x+10x236=-14x+10x^2

hence

−10x2+14x+36=0-10x^2+14x+36=0

10x2−14x−36=010x^2-14x-36=0

5x2−7x−18=05x^2-7x-18=0

x=2.722x=2.722

hence x=3x=3 units


in Plant 2

MR=MCMR=MC2

396−12x2=310−15x−x2396-12x^2=310-15x-x^2

86=−15x+11x286=-15x+11x^2

−11x2+15x+86=0-11x^2+15x+86=0

11x2−15x−86=011x^2-15x-86=0

x=3.5598x=3.5598

hence x=4x=4 units


LATEST TUTORIALS
APPROVED BY CLIENTS