Question #129975

Suppose the demand for money is L=0.20Y, the money supply is 200, consumption:
C=90+0.80YD, taxes T=50, Investment: I=140-5r, and government purchases: G=50.
ii) Find equilibrium output, and the rate of interest

Expert's answer

SolutionSolution

To solve for the equilibrium levels of output (Y) and interest rate (r). We solve the system of two equations with two unknowns (Y and r) from IS and LM relations.


IS equation is derived from :

Y=C+I+GY=C+I+G

Y=90+0.80YD+1405r+50Y=90+0.80YD+140-5r+50

Y=90+0.80(YT)+1405r+50Y=90+0.80(Y-T)+140-5r+50

Y=90+0.80Y0.80(50)+1405r+50Y=90+0.80Y-0.80(50)+140-5r+50

Y=90+0.80Y40+1405r+50Y=90+0.80Y-40+140-5r+50

Y=0.80Y+2405rY=0.80Y+240-5r

Y0.80Y=2405rY-0.80Y=240-5r

0.02Y=2405r0.02Y=240-5r

Y=120025rY=1200-25r

IS  equation:Y=120025rIS \; equation: Y=1200-25r


LM equation:

equate Money supply with Money demand

(M/P)s=(M/P)d(M/P)^{s} = (M/P)^{d}

200=0.20Y200=0.20Y

0.20Y=2000.20Y=200

Y=2000.20Y=\frac{200}{0.20}


Y=1,000Y= 1,000

LM  equation:Y=1,000LM \;equation: Y=1,000


Now We have the equilibrium levels of output Y=1,000


We now sub this value for Y into the IS relation to find the corresponding value for r:


1000=120025r25r=12001000    25r=200    r=8%1000=1200−25r\\ 25r=1200-1000 \implies 25r=200 \implies r=8\%

Interest rate (r)=8%







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