Question #123004
Given the following:
C = 2000 + 0.75Yd
T = 300
I = 320
G = 300
X = 300
M=100


a) Determine the equilibrium level of income using expenditure and injection-leakage approach

b) Determine the value of C at equilibrium level of income.

c) Calculate the equilibrium level of income when there is an increase in investment of 100 using expenditure and multiplier approach.
1
Expert's answer
2020-06-21T19:54:07-0400

a) Determine the equilibrium level of income using expenditure and injection-leakage approach


We have the data:


C=2000+0.75YdT=300I=320G=300X=300M=100C = 2000 + 0.75Yd\\[0.3cm] T = 300\\[0.3cm] I = 320\\[0.3cm] G = 300\\[0.3cm] X = 300\\[0.3cm] M=100


The expenditure approach method is:



Y=C+I+G+(XM)Y= C + I + G + (X - M)\\[0.3cm]

Therefore:



Y=2000+0.75(Y300)+320+300+(300100)Y=2820+0.75Y2250.25Y=2595Y=25950.25=10,380Y = 2000 + 0.75(Y - 300) + 320 + 300 + (300 - 100)\\[0.3cm] Y = 2820+ 0.75Y - 225 \\[0.3cm] 0.25Y = 2595\\[0.3cm] Y^* = \dfrac{2595}{0.25} = \color{blue}{10,380}

b) Determine the value of C at equilibrium level of income.



C=2000+0.75(10,380300)C=9,560C = 2000 + 0.75(10,380 - 300)\\[0.3cm] \color{red}{C = 9,560}

c) Calculate the equilibrium level of income when there is an increase in investment of 100 using expenditure and multiplier approach.


The multiplier is given by:



k=ΔYΔI=11MPCk = \dfrac{\Delta Y}{\Delta I} = \dfrac{1}{1 - MPC}

In our question, MPC = 0.75. Therefore:



k=110.75=4k = \dfrac{1}{1 - 0.75} = 4

When the investment increases by 100, the equilibrium income will increase by:



ΔY=4×Δ100ΔY=400\Delta Y = 4\times \Delta 100\\[0.3cm] \Delta Y = 400

The new income is:



Y=10,380+400=10,780Y^{**} = 10,380 + 400 = \color{blue}{10,780}


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