Question #123004

Given the following:

C = 2000 + 0.75Yd

T = 300

I = 320

G = 300

X = 300

M=100



a) Determine the equilibrium level of income using expenditure and injection-leakage approach



b) Determine the value of C at equilibrium level of income.


c) Calculate the equilibrium level of income when there is an increase in investment of 100 using expenditure and multiplier approach.

Expert's answer

a) Determine the equilibrium level of income using expenditure and injection-leakage approach


We have the data:


C=2000+0.75YdT=300I=320G=300X=300M=100C = 2000 + 0.75Yd\\[0.3cm] T = 300\\[0.3cm] I = 320\\[0.3cm] G = 300\\[0.3cm] X = 300\\[0.3cm] M=100


The expenditure approach method is:



Y=C+I+G+(XM)Y= C + I + G + (X - M)\\[0.3cm]

Therefore:



Y=2000+0.75(Y300)+320+300+(300100)Y=2820+0.75Y2250.25Y=2595Y=25950.25=10,380Y = 2000 + 0.75(Y - 300) + 320 + 300 + (300 - 100)\\[0.3cm] Y = 2820+ 0.75Y - 225 \\[0.3cm] 0.25Y = 2595\\[0.3cm] Y^* = \dfrac{2595}{0.25} = \color{blue}{10,380}

b) Determine the value of C at equilibrium level of income.



C=2000+0.75(10,380300)C=9,560C = 2000 + 0.75(10,380 - 300)\\[0.3cm] \color{red}{C = 9,560}

c) Calculate the equilibrium level of income when there is an increase in investment of 100 using expenditure and multiplier approach.


The multiplier is given by:



k=ΔYΔI=11MPCk = \dfrac{\Delta Y}{\Delta I} = \dfrac{1}{1 - MPC}

In our question, MPC = 0.75. Therefore:



k=110.75=4k = \dfrac{1}{1 - 0.75} = 4

When the investment increases by 100, the equilibrium income will increase by:



ΔY=4×Δ100ΔY=400\Delta Y = 4\times \Delta 100\\[0.3cm] \Delta Y = 400

The new income is:



Y=10,380+400=10,780Y^{**} = 10,380 + 400 = \color{blue}{10,780}


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