a)C=50+0.80×(Y−T)=50+0.80Y−0.8×50=50+0.8Y−40=10+0.8Y;
Y=C+I+G;
Y=10+0.8Y+200+100;Y=310+0.8Y;
0.2Y=310;
Y=1550;
b)
G=125;
Y=10+0.8Y+200+125;Y=335+0.8Y;
0.2Y=335;
Y=1675;
c) 2000=10+0.8∗2000+200+G;
2000=10+1600+200+G;
G=2000−10−1600−200;G=190
Answer: G equally 190.
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