200(1-MPC)=200
MPC=0
b.M=ΔYΔI=200200=1M=\frac{\Delta Y}{\Delta I}=\frac{200}{200}=1M=ΔIΔY=200200=1
2 a.ΔY(1−MPC)=ΔI\Delta Y(1-MPC)=\Delta IΔY(1−MPC)=ΔI
160 =(1-MPC)=200
MPC=0.25
b.M=ΔYΔI=160200=0.8M=\frac{\Delta Y}{\Delta I}=\frac{160}{200}=0.8M=ΔIΔY=200160=0.8
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