(b) We shall calculate the average return bybthe formula
Average return =initialinvestmentaverageinvestment
The average investment from January through to June is given by
=695.5
=15.92
Now,
Averagereturn=15.2515.92
=1.04
(C) To calculate the standard deviation
S.D=n∑(x−xˉ)2
Where xˉ Is the average value (the mean) in question (b) which is
xˉ=15.92
∑(x−xˉ)2=(15.25−15.92)2+(16.10−15.92)2+(16.20−15.92)2+(15.80−15.92)2+(15.85−15.92)2+(16.30−15.92)2
∑(x−xˉ)=0.4489+0.0324+0.0729+0.0144+0.0049+0.1444
∑(x−xˉ)2=0.7179
Therefore,
S.D=n∑(x−xˉ)2
S.D=60.7179
S.D=0.11965S.D=0.3459
HENCE,
(a)the monthly holding -period return is
0.06%
(b)the average return is
1.04%
(c)the standard deviation is
0.3459
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