Given the end-of-month prices for stock X for January 2020 through June 2020,
Month End-of-Month Price
January 2020 15.25
February 2020 16.10
March 2020 16.20
April 2020 15.80
May 2020 15.85
June 2020 16.30
calculate
a. Monthly holding-period return
b. Average Return
c. Standard Deviation
(b) We shall calculate the average return bybthe formula
Average return "=\\frac{average \\hspace{0.1cm}investment}{initial \\hspace{0.1cm}investment}"
The average investment from January through to June is given by
"=\\frac{95.5}{6}"
"=15.92"
Now,
"Average \\hspace{0.1cm}return=\\frac{15.92}{15.25}"
"=1.04"
(C) To calculate the standard deviation
"S.D=\\sqrt{\\frac{\\sum(x-\\bar{x})\u00b2}{n}}"
Where "\\bar{x}" Is the average value (the mean) in question (b) which is
"\\bar{x}=15.92"
"\\sum({x-\\bar{x}})\u00b2=(15.25-15.92)\u00b2 +(16.10-15.92)\u00b2+(16.20-15.92)\u00b2+(15.80-15.92)\u00b2+(15.85-15.92)\u00b2+(16.30-15.92)\u00b2"
"\\sum({x-\\bar{x}})=0.4489+0.0324+0.0729+0.0144+0.0049+0.1444"
"\\sum({x-\\bar{x}})\u00b2=0.7179"
Therefore,
"S.D=\\sqrt{\\frac{\\sum(x-\\bar{x})\u00b2}{n}}"
"S.D=\\sqrt{\\frac{0.7179}{6}}"
"S.D=\\sqrt{0.11965}\\\\S.D=0.3459"
HENCE,
(a)the monthly holding -period return is
0.06%
(b)the average return is
1.04%
(c)the standard deviation is
0.3459
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