Question #281475

a) You have RM 33 750 in a brokerage account, and you plan to have an account totals

RM 72 863.72. You expect to earn 8% annually on the account. How many years will it take to reach your goal? (3 Marks)

b) If you deposit RM 27 590 in a bank account that pays 13% interest annually, how much will be in your account after 7 years? (2 Marks) c) How long does it take to double your money, given the interest rate is 10%? (2 Marks)

d) Find the amount to which RM 4000 will grow if it is 11% compounded quarterly for 7 years. (3 Marks)

e) It is now January 1 st 2015, and you will need RM 55 570 on January 1 st 2019, in 4 years. Your bank compounds interest at an 7% annual rate.

i) How much must you deposit today to have balance of RM 55 500 on January 1 st

2019? (2 Marks)

ii) How much do you have to deposit today if the bank uses semi-annually compounding? (3 Marks)


1
Expert's answer
2021-12-21T08:34:38-0500

Answer (a):

PV = RM 33750

FV = RM 72863.72

r = 8% annually

FV=PV(1+r)nFV=PV(1+r)^n

72863.72=33750(1+0.08)n72863.72=33750(1+0.08)^n

(1.08)n=72863.7233750(1.08)^n=\frac{72863.72}{33750}

(1.08)n=2.1589(1.08)^n=2.1589

Take log of both side

nln(1.08)=ln(2.1589)nln(1.08)=ln(2.1589)

n=ln(2.1589)ln(1.08)=10n=\frac{ln(2.1589)}{ln(1.08)}=10

This means at least 10 years will be needed to reach goal.


Answer (b):

PV = RM 27590

r = 13% interest annually

Time period = 7 years

FV=PV(1+r)nFV=PV(1+r)^n

FV=27590×(1+0.13)7FV=27590\times(1+0.13)^7

FV=64,908.39FV=64,908.39

This means the account will have $64,908.39 after 7 years.


Answer (c):

PV = RM 27590

FV = RM 55180

r = 10% annually

FV=PV(1+r)nFV=PV(1+r)^n

55180=27590(1+0.10)n55180=27590(1+0.10)^n

(1.10)n=5518027590(1.10)^n=\frac{55180}{27590}

(1.10)n=2(1.10)^n=2

Take log of both side

nln(1.10)=ln(2)nln(1.10)=ln(2)

n=ln(2)ln(1.10)=7.277n=\frac{ln(2)}{ln(1.10)}=7.27\approx7

This means 7 years will be needed to double money.


Answer (d):

PV = RM 4000

r = 11% compounded quarterly

n = 7 years

FV=PV×(1+rm)mnFV=PV\times (1+\frac{r}{m})^{mn}

FV=4000×(1+0.114)4×7FV=4000\times (1+\frac{0.11}{4})^{4\times7}

FV=4000×(1+0.0275)28FV=4000\times (1+0.0275)^{28}

FV=$8549.71FV=\$8549.71


Answer (e):

i):

FV = RM 55570

n = 4 years

r =7% annually

PV=FV(1+r)nPV=\frac{FV}{(1+r)^n}

PV=55570(1+0.07)4PV=\frac{55570}{(1+0.07)^4}

PV=$42394.09PV=\$42394.09


ii):

FV = RM 55570

n = 4 years

r =7% annually

PV=FV(1+rm)mnPV=\frac{FV}{(1+\frac{r}{m})^{mn}}

PV=55570(1+0.072)2×4PV=\frac{55570}{(1+\frac{0.07}{2})^{2\times4}}

PV=55570(1+0.035)8PV=\frac{55570}{(1+0.035)^{8}}

PV=$42200.50PV=\$42200.50




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