Question #217860


Down-To-Earth sells houses. The following table represents the selling price of a house (y) in thousands of rands and the number of houses sold at that price (x):

x 5 15 19 7

y 500 900 1500 2 000

The standard deviation for the number of houses sold is

[1] 6,6.

[2] 4,0.

[3] 11,5.

[4] 5,7.

[5] none of the above.



Expert's answer

we have to find the standard deviation for the number of

 houses sold

so  the given data is 5,15,19,7

mean xˉ=5+15+19+75=11.5\bar{x}=\frac{5+15+19+7}{5}=11.5

standard deviation (s)=∑1(x1−xˉ)n−1=\sqrt{\frac{\displaystyle\sum_{1}(x_1-\bar{x})}{n-1}}

=(5−11.5)2+(15−11.5)2+(19−11.5)2+(7−11.5)25−1=\frac{\sqrt{(5-11.5 )^2+(15-11.5)^2 +(19-11.5)^2 +(7-11.5)^2}}{5-1}

=43.666667=6.6=\sqrt{43.666667}\\=6.6


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