The number of years to reach the desired value is:
n=ln(1+(1,200,000−400,000)×0.1/50,000)ln(1+0.1)=ln(2.6)ln(1.1)=10.025n = \frac{ln(1 + (1,200,000 - 400,000)×0.1/50,000) } {ln(1 + 0.1)} = \frac{ln(2.6)} {ln(1.1)} = 10.025n=ln(1+0.1)ln(1+(1,200,000−400,000)×0.1/50,000)=ln(1.1)ln(2.6)=10.025
or approximately 10 years.
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