0=(500∗(1+i12)3−300)∗(1+i12)3−3000=(500*(1+\frac{i}{12})^3-300)*(1+\frac{i}{12})^3-3000=(500∗(1+12i)3−300)∗(1+12i)3−300
(1+i12)3=t(1+\frac{i}{12})^3=t(1+12i)3=t
0=500∗t2−300∗t−3000=500*t^2-300*t-3000=500∗t2−300∗t−300
t=3−8.3110t=\frac{3-8.31}{10}t=103−8.31 - less than 0, interest rate can't be less than 0
t=3+8.3110=1.131t=\frac{3+8.31}{10}=1.131t=103+8.31=1.131
(1+i12)3=1.131(1+\frac{i}{12})^3=1.131(1+12i)3=1.131
i=0.5027=50.27%i=0.5027=50.27\%i=0.5027=50.27%
i-annual interest rate
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