x∗0.08=3000x*0.08=3000x∗0.08=3000
x=37,500x=37,500x=37,500 - amount at the end of 11 years
37,500=A∗1.08(1−1.0810)−0.08∗1.0837,500=A*\frac{1.08(1-1.08^{10})}{-0.08}*1.0837,500=A∗−0.081.08(1−1.0810)∗1.08
A=2,219.31A=2,219.31A=2,219.31
A - annual deposit
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