TC= 103+15q-6q^2+q^3
Find VC , MC, AVC
Value of FC + VC when out put (q )= 0.5
VC = 15q−6q2+q315q-6{q^2}+{q^3}15q−6q2+q3
MC = dMCdq=15−12q+3q2\frac{dMC}{dq} =15-12q+3{q^2}dqdMC=15−12q+3q2
AVC = VCq\frac{VC}{q}qVC
AVC = 15q−6q2+q3q\frac{15q-6{q^2}+{q^3}}{q}q15q−6q2+q3
AVC = 15−6q+q215-6q+{q^2}15−6q+q2
FC = 103
VC = 15(0.5)−6(0.52)+0.5315(0.5)-6({0.5^2})+{0.5^3}15(0.5)−6(0.52)+0.53
VC = 6.125
FC + VC = 103+6.125
Value = 109.125
Need a fast expert's response?
and get a quick answer at the best price
for any assignment or question with DETAILED EXPLANATIONS!
Comments
Leave a comment