A firm borrows P2,000 for 6 years at 8%. At the end of 6 years, it renews the loan for the amount due plus P2,000 more for 2 years at 8%. What is the lump sum due?
A1=6000(0.0067+0.0067(1+0.0067)72−1)=104.79A1=6000(0.0067+\frac{0.0067}{(1+0.0067)^{72}-1})=104.79A1=6000(0.0067+(1+0.0067)72−10.0067)=104.79
104.79×72=7545,075104.79\times72=7545,075104.79×72=7545,075
7545,075+2000=9545,075
A2=9545.075(0.0067+0.0067(1+0.0067)24−1)=429.7234A2=9545.075(0.0067+\frac{0.0067}{(1+0.0067)^{24}-1})=429.7234A2=9545.075(0.0067+(1+0.0067)24−10.0067)=429.7234
429.7234×24=10313.36429.7234\times24=10313.36429.7234×24=10313.36
Need a fast expert's response?
and get a quick answer at the best price
for any assignment or question with DETAILED EXPLANATIONS!
Comments