Answer to Question #259724 in Economics of Enterprise for Via

Question #259724

Given the Total cost Function, TC = 5,600 + 27Q - 6Q² - .5Q³, solve for AC, MC, AVC and AFC





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Expert's answer
2021-11-03T10:40:58-0400

Given;TC=5600+27Q6Q20.5Q3AC=TCQ=5600Q+276Q0.5Q2MC=dTCdQ=2712Q1.5Q2AVC=VCQ=27Q6Q20.5Q3Q=276Q0.5Q2AFC=FCQ=5600QGiven;\\ TC=5600+27Q−6Q^2−0.5Q^3\\ AC=\frac{TC}{Q}\\ =\frac{5600}{Q}+27−6Q−0.5Q^2\\ MC=\frac{dTC}{dQ}\\ =27−12Q−1.5Q^2\\ AVC=\frac{VC}{Q}\\ =\frac{27Q−6Q^2−0.5Q^3}{Q}\\ =27−6Q−0.5Q^2\\ AFC=\frac{FC}{Q}\\ =\frac{5600}{Q}


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