Given the Total cost Function, TC = 5,600 + 27Q - 6Q² - .5Q³, solve for AC, MC, AVC and AFC
Given;TC=5600+27Q−6Q2−0.5Q3AC=TCQ=5600Q+27−6Q−0.5Q2MC=dTCdQ=27−12Q−1.5Q2AVC=VCQ=27Q−6Q2−0.5Q3Q=27−6Q−0.5Q2AFC=FCQ=5600QGiven;\\ TC=5600+27Q−6Q^2−0.5Q^3\\ AC=\frac{TC}{Q}\\ =\frac{5600}{Q}+27−6Q−0.5Q^2\\ MC=\frac{dTC}{dQ}\\ =27−12Q−1.5Q^2\\ AVC=\frac{VC}{Q}\\ =\frac{27Q−6Q^2−0.5Q^3}{Q}\\ =27−6Q−0.5Q^2\\ AFC=\frac{FC}{Q}\\ =\frac{5600}{Q}Given;TC=5600+27Q−6Q2−0.5Q3AC=QTC=Q5600+27−6Q−0.5Q2MC=dQdTC=27−12Q−1.5Q2AVC=QVC=Q27Q−6Q2−0.5Q3=27−6Q−0.5Q2AFC=QFC=Q5600
Need a fast expert's response?
and get a quick answer at the best price
for any assignment or question with DETAILED EXPLANATIONS!
Comments
Leave a comment