Answer to Question #257247 in Economics of Enterprise for moatasem

Question #257247

Claudia has sold her car and received approval from the garage owner to re-lease her downtown reserved parking spot for the next four months so she can make some extra money. The rental fee is $200 per month, and she expects to charge $18 per day. Transportation in a car pool will cost her $6 per day. If there are a maximum of 20 work days per month for re-leasing the spot, determine the following: a. Total cost and revenue relations b. Breakeven quantity per month c. Amount of money she will make (or lose) if the number of re-leased days per month over the four-month period are 18, 12, 17, and 20.


1
Expert's answer
2021-10-27T08:30:32-0400

(a)

Total cost=rental fee+ transportation fee.

In a month:

=200+(6×20)=320.=200+(6\times20)=320.

In 4 months:

=320×4=320\times4

=$1280

Total revenue in a month: =18×20=360.=18\times20=360.

In 4 months:

360×4=1440360\times4=1440

=$1440.


(b)

Break even quantity per month:

=FixedCostPVC=\frac{Fixed Cost}{P-VC}

=200(18×20)(6×20)=\frac{200}{(18\times20)-(6\times20)}

=0.8=0.8

(c)

Profit for 18 days:

Total cost =200+(6×18)=308.200+(6\times18)=308.

Total revenue=18×18=324=18\times18=324

Profit =324308=16=324-308=16


For 12 days:

Total cost=200+(6×12)=272=200+(6\times12)=272

Total revenue=18×12=216=18\times12=216

Here, a loss of $56 is made.


For 17 days:

Total cost =200+(6×17)=302=200+(6\times17)=302

Total revenue=18×17=306.=18\times17=306.

Profit =306302=4=306-302=4


For 20 days:

Total cost =200+(6×20)=320.=200+(6\times20)=320.

Total revenue=18×20=360.=18\times20=360.

Profit =360320=40=360-320=40

=$40.


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