A man borrows ₱6,400 from a loan association. In repaying this debt he has to pay ₱400 at the end of every 3 months on the principal and a simple interest of 16% on the principal outstanding at that time. Determine the total amount he has paid after paying all his debt.
Solution:
The correct answer is ₱8,576.00.
"\\frac{3}{12} = 0.25"
Interest 1 = 6400 "\\times" 0.25 "\\times" 0.16 = 256
Interest 2 = 6000 "\\times" 0.25 "\\times" 0.16 = 240
Interest 16 = 400 "\\times" 0.25 "\\times" 0.16 = 16
Total Principal = 6400 + S
S = "\\frac{n}{2} \\times" (a1 +an) = "\\frac{16}{2} \\times (256 + 16) = 2,176"
TP = 6400 + 2176 = 8576
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