1. Given TC = 100 + 60Q – 12Q2 + Q3, find:
a. The equations of the TVC, AVC, and MC functions.
b. The level of output at which AVC and MC are minimum, and prove that the AVC and MC curves are U-shaped.
c. Find the AVC and MC for the level of output at which the AVC curve is minimum.
From the Total cost TC ;If Q=0,TC=100 and TFC=100
Therefore TVC=60Q-12Q2+Q3
AVC="\\frac{TVC} {Q}" ="\\frac{(60Q\u221212Q2+Q3)} {Q}"
AVC=60-12Q+Q2
MC="\\frac{d(TC)} {dq}" ="\\frac{d(60Q-12Q^2+Q^3)} {dq}"
MC=60-24Q+3Q2
b) For Minimum Output AVC ;"\\frac{d(AVC)} {dq} =0"
"\\frac{d(60-12Q+Q^2) }{dq} =0"
"\\frac{d(AVC)} {dQ}" =-12 +2Q=0
Q=6
Hence AVC is minimum when output, Q=6
For Minimum output MC; 60-24Q+3Q2
"\\frac{d(MC)} {dQ}" =-24+6Q=0
Q=4
Hence MC is minimum when output, Q=4
To prove that AVC and MC curves are U shaped ;
"\\frac{d(MC)} {dQ}" =-24+6Q
"\\frac{d2(MC)} {d2(Q)}" =6>0, hence the curves are U shaped.
c) AVC=60 - 12Q+Q2
60-12(6)+62
60-72+36
=24
The output level Q=6 at which AVC function is minimum, AVC and MC is 24.
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