Answer on Question #98783 – Chemistry – Other
Task:
Consider the reaction 3CaCl2(aq) + 2Na3PO4(aq) --> Ca3(PO4)2(s) + 6NaCl(aq) (molar mass of calcium phosphate is 310.18 g/mol)
What volume of 0.500 M Na3PO4 solution is needed to react with 275 mL of 0.150 M CaCl2? _____ mL (Give answer to correct sig figs in units of mL).
Solution:
Balanced equation:
3CaCl2 + 2Na3PO4 --> Ca3(PO4)2 + 6NaCl
According to the reaction equation: n(CaCl2) / 3 = n(Na3PO4) / 2;
2*n(CaCl2) = 3*n(Na3PO4);
n = C*V, then:
2 * C(CaCl2) * V(CaCl2) = 3 * C(Na3PO4) * V(Na3PO4);
2 * 0.150 M * 275 mL = 3 * 0.500 M * V(Na3PO4);
82.5 = 1.5 * V(Na3PO4);
V(Na3PO4) = 82.5 / 1.5 = 55 mL
V(Na3PO4) = 55.0 mL.
Answer: V(Na3PO4) = 55.0 mL.
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