Answer to Question #95796 in Chemistry for Caroline Hudgins

Question

determine the mass of a sample of 3.6moles of CaCl2

Answer 1

Answer on Question #95796 – Chemistry – Other

Task:

Determine the mass of a sample of 3.6 moles of CaCl₂

Solution:

1) The molar mass of calcium chloride (CaCl₂):

M(CaCl₂) = Ar(Ca) + 2*Ar(Cl) = 40.078 + 2*35.453 = 110.984 (g/mol);

2) n(CaCl₂) = m(CaCl₂) / M(CaCl₂);

Then,

m(CaCl₂) = n(CaCl₂)*M(CaCl₂) = 3.6 mol * 110.984 g/mol = 399.542 g;

m(CaCl₂) = 399.542 g

Answer: the mass of 3.6 moles of CaCl₂ is 399.542 grams.